Question

How do I use the quadratic formula to solve this equation 4x^2-6x-10=0

Answer 1

4x^2-6x-10=0

is like:
Ax^2+Bx+C=0

A=4
B=-6
C=-10


\[\frac{ -B \pm \sqrt{B^2-4AC} }{ 2A } = X\]

Answer 2

so i just plug in the rite numbers in da quad form?

Answer 3

yep ^_^

you will do the equation twice, because there is the plus minus symbol.
so the first time you can do plus
and the second time you can do minus

Answer 4

ok let me solve this and then can u check it?

Answer 5

yep ^_^

Answer 6

is it -1 and/or 5/2?

Answer 7

good job ^_^
-1 and 5/2 is correct

Answer 8

thx :D