Question

x^2+4x=5 how do i solve?

Answer 1

I use wolframalpha OwO http://www.wolframalpha.com/input/?i=x%5E2%2B4x%3D5 x = -5 and x = 1

Answer 2

no char how do i solve it myself?

Answer 3

try guessing small integers for x and see what you get.

Answer 4

ehh nvm i got it

Answer 5

I'll give you a detailed explanation.
x^2+4x=5
you subtract from both sides the 5.
x^2 + 4x - 5 = 0
Then you use the magical quadratic formula.
\[x=\frac{ -b \pm \sqrt {b^2 -4(a)(c)} }{ 2(a) }\]

Answer 6

Inputting your values of a, b, c.
a = 1 , b = 4 , c = -5.
\[x = \frac{ -4 \pm \sqrt { 16 + 20} }{ 2 } = \frac{ -4 \pm 6 }{ 2} \]
\[\frac{ -4 + 6 }{ 2 } = 1\]
\[\frac{ -4 - 6 }{ 2 } = -5\]
your solutions are x = 1 , and x = -5

Answer 7

what sham said O_O