Can you tell me how to write the equation for the horizontal line that contains point G(-8, 8)?
A horizontal line has no slope. So when calculating your equation of a line, you want to use point-slope form: (y - y1) = m(x - x1), where (x1,y1) is your coordinates. So... (y - 8) = 0 (x - (-8)) y - 8 = 0 y = 8 Now if you want to think about it, this line extends horizontal, so it runs parallel to the x-axis. It must go through that point, so it has to be y = 8 and only y = 8 for it to remain perfectly horizontal while going through that point.
U mean like this? m = 0 x1 = -8 y1 = 8 y - 8 = 0(x - (-8)) y - 8 = 0 y = 8 Is that correct?
Yes
Oh thank u sooooooo much! I think I got it :)
My Pleasure.
So how will I give u a reward? This is ,y first time in open study....
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