Question

Determine any restrictions on the variable.
5y^2/3y-4

Answer 1

you just have to see how there can be a zero in the denominator

Answer 2

Thank you but can you explain how I work it out?
3y-4=0? Now what?

Answer 3

okay so solve for y

Answer 4

sometimes though it might not be a restriction still so we must check

Answer 5

Ok I got it. How do I know if it is a restriction or not?

Answer 6

well if it as indeterminante form like
if you have 0/0 or inf/inf or 0/inf

Answer 7

in this case we dont have that because the bottom is zero when y = 4/3
but the top which is 5*(4/3)^2 wont be zero so you are fine

Answer 8

means there as an asymtote at y=4/3

Answer 9

Ok. I have another problem that i am not quite sure how to work out. x+1/x^2-4x?

Answer 10

factor the bottom and see what can make the bottom 0