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Determine any restrictions on the variable. x^2+2x/x^2+4
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set the denominator equal to ZERO. and solve for x.
Restrictions are just when your denominator = 0. So yes, do what @SolomonZelman says.
x^2=-4?
it is always the case that \(x^2\geq 0\) and so \(x^2+4\geq 4\) i.e. it is never zero, so no restrictions
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