Question

Find the derivatives.
p(x)=(3x^2-1)(7+2x^3)

Answer 1

use product rule @malibugranprix2000 !

Answer 2

I see that the product rule is used, but I am not sure how to figure it out still?

Answer 3

(uv)'=uv'+vu'

Answer 4

u-(3x^2-1)
v-(7+2x^3)

Answer 5

(3x^2-1)(7+2x^3)'+(7+2x^3)(3x^2-1)'

Answer 6

'-derivative

Answer 7

(7+2x^3)'=(0+2(3x^2))=6x^2

Answer 8

(3x^2-1)'=(3*2x)

Answer 9

is it clear @malibugranprix2000 ?

Answer 10

can u proceed from here ?

Answer 11

@CGGURUMANJUNATH, yes I will work on it.

Answer 12

very good.

Answer 13

if you are not clear at any step kindly ask me . @malibugranprix2000

Answer 14

@CGGURUMANJUNATH thanks for the help so far :)

Answer 15

:)