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Help with L'hopitals?
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lim x→0 (3x + sin x)/(6x + cos x)
so did you differentiate the numerator and denominator separately ?
Yes. I get 3+cosx/ 6-sinx
correct!
now you can just plug in x= 0 in that :)
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I get 2/3 but the answer says 0?
oh wait!
you don't need L'Hopital's here! you can directly put x=0 in the original function and you do not get a 0/0 or infinity/infinity form!
you know right ? that we use LH rule only if we have 0/0 or infinity/infinity form ?
Is it okay to use this rule when you have a number/0 ?
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nopes, LHrule can be used only with these 2 forms 0/0 and infinity/infinity
a positive number /0 = +infinity a negative number /0 = -infinity
Okay, thank you!
welcome ^_^
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