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Mathematics 15 Online
OpenStudy (anonymous):

Help with L'hopitals?

OpenStudy (anonymous):

lim x→0 (3x + sin x)/(6x + cos x)

hartnn (hartnn):

so did you differentiate the numerator and denominator separately ?

OpenStudy (anonymous):

Yes. I get 3+cosx/ 6-sinx

hartnn (hartnn):

correct!

hartnn (hartnn):

now you can just plug in x= 0 in that :)

OpenStudy (anonymous):

I get 2/3 but the answer says 0?

hartnn (hartnn):

oh wait!

hartnn (hartnn):

you don't need L'Hopital's here! you can directly put x=0 in the original function and you do not get a 0/0 or infinity/infinity form!

hartnn (hartnn):

you know right ? that we use LH rule only if we have 0/0 or infinity/infinity form ?

OpenStudy (anonymous):

Is it okay to use this rule when you have a number/0 ?

hartnn (hartnn):

nopes, LHrule can be used only with these 2 forms 0/0 and infinity/infinity

hartnn (hartnn):

a positive number /0 = +infinity a negative number /0 = -infinity

OpenStudy (anonymous):

Okay, thank you!

hartnn (hartnn):

welcome ^_^

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