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Is y=x^(2/3) continuous and differentiable?
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It is continuous, but not differentiable due to x being in the denominator in its derivative. The derivative would not exist at x=0.
Thank you very much! I wasn't sure if it was continuous in the first place since there seems to be a cusp and an imaginary part, but the x in the denominator makes sense!
Ah but it would only reach the imaginary numbers if you used the principle root (a root of a number has 2 parts, a negative and positive; principle root is only the positive). However, if you allow both roots, the graph would actually just touch (0,0) then mirror itself along the y-axis!
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