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Mathematics 5 Online
OpenStudy (anonymous):

Can someone check this for me? (completing the square)

OpenStudy (anonymous):

y = -2x^2 - 20x - 48

OpenStudy (anonymous):

then i rewrote that into: y = -2(x^2 - 20x ____) -48 -20/2 = -10 then square it and I got 100 y = -2(x^2 - 20x +100) -48

OpenStudy (anonymous):

then I added 100 to both sides and I got: y + 100= -2(x - 10)^2 -48 -100 -100 ------------------------ y = -2(x - 10)^2 - 148

OpenStudy (anonymous):

You subtracted 100 though ^

OpenStudy (anonymous):

you add 48 to the other side and then also the 100 and the quadratic = 148

OpenStudy (anonymous):

then you can factor the left side

OpenStudy (anonymous):

can you show me that in steps? like from the beginning

OpenStudy (anonymous):

you did it rite just set the equation = 0 then subtract 49 from both sides so 2x^2-20x=48

OpenStudy (anonymous):

then complete the square and add the 100 to both sides

OpenStudy (anonymous):

so it'd be 0 = -2(x^2 - 20x + 100) -48 ?

OpenStudy (anonymous):

why do I need to factor that

OpenStudy (anonymous):

Ok I got it thanks! and one more question

OpenStudy (anonymous):

How would I solve: x^2 - 38x + c also by completing the square

OpenStudy (anonymous):

c is a constant most likely just move it to the other side and complete the square

OpenStudy (anonymous):

what is that going to give me?

OpenStudy (anonymous):

x^2-38x=c

OpenStudy (anonymous):

and what would be the next step

OpenStudy (anonymous):

0 = (x2 - 38x ___) +c ?

OpenStudy (anonymous):

square the -38 and do the same to both sides

OpenStudy (anonymous):

(x^2-38x+__)=__-c

OpenStudy (anonymous):

-38/2 = -19^2 = 361

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

so that is on both sides

OpenStudy (anonymous):

(x^2-38x+361)=361-c

OpenStudy (anonymous):

okay so far i have: (x^2 - 38x + 361) = 361 -c

OpenStudy (anonymous):

right now you should be able to factor the quadratic which is the point of completing the square

OpenStudy (anonymous):

so like: ____ x___ = 361 ____+___= -38

OpenStudy (anonymous):

right it will be the same number it is squared

OpenStudy (anonymous):

-19

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

(x-19)^2 = 361 - c?

OpenStudy (anonymous):

and the first equation was x^2-10+25=49

OpenStudy (anonymous):

right

OpenStudy (anonymous):

what do I do now?

OpenStudy (anonymous):

with the second you can't do anything it is most likely to show how you did the work

OpenStudy (anonymous):

x-5=7

OpenStudy (anonymous):

so just that ^

OpenStudy (anonymous):

how would i write tht in intercept form

OpenStudy (anonymous):

do you mean y=mx+b

OpenStudy (anonymous):

no I also have to rewrite tht in intercept

OpenStudy (anonymous):

the x intercept is +or-(7/5,0)

OpenStudy (anonymous):

that is the y is 0

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