Question

C= .55t^2 + 550.
C= $1430 and t is the number of months.
How do I solve this?

Answer 1

Before you guys comment, I want to thank you for taking the time to help me out. It means a ton.

Answer 2

It seems like you need to solve for t?
\[1430=.55t^2+550\]so move everything to the left side.\[\frac{ 1430-550 }{ .55 }=t^2\]We what we have to get:
\[1600=t^2\]Now we take the square root of both sides.
\[\sqrt{1600}=\sqrt{t^2}\rightarrow t=40\]

Answer 3

I'm guessing this is some kind of interest problem.
1,430 = .55t² + 550
.55t² = 1,430 - 550
.55t² = 880
t² = 1,600
t = 40

Answer 4

looks as if we have a consensus on this

Answer 5

Thanks guys! I wish I can give two medals!

Answer 6

thanks grayp