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my son has a question on his homework that has me stumped
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ok shoot
^
He's got c over 4 minus 1 over 12 = 2 over three. I realize he has to solve for c, but I have completely forgotten how to start this.
\[\frac{c}{4} = \frac{2}{3} + \frac{1}{12}\] \[c = 4(\frac{2}{3} + \frac{1}{12})\] remember how to add fractions
He got 1 and 1 sixth...is he right?
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...or 7/6.
how do you minus fractions ?
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