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OpenStudy (anonymous):

What is the solution of the system of equations?

OpenStudy (anonymous):

OpenStudy (anonymous):

eliminate variables one by one...

OpenStudy (anonymous):

ok...

OpenStudy (anonymous):

solved

OpenStudy (anonymous):

solved?

OpenStudy (anonymous):

is there a specific method you need to solve this? because i would use cramer's rule or put it to rref to solve this

OpenStudy (anonymous):

No:/ It just says that I need to solve the system. What's cramer's rule?

OpenStudy (anonymous):

cramer's rule is from linear algebra im assuming you're not suppoed to do it that way if they didnt teach your it im thinking your prob gonna need to do it the long way

OpenStudy (anonymous):

Oh joy the long way. Okay can you help me with it?

OpenStudy (anonymous):

I did a system of equation...

OpenStudy (anonymous):

so first eliminate the x's and y's by subtracting equation 1 from 3

OpenStudy (anonymous):

and so you get -2z=6. hence z=-3

OpenStudy (anonymous):

plug it back into the equations to get new equations: 5x+5y=15 and 3x+2y=10

OpenStudy (anonymous):

now solve for y by eliminating x :D

OpenStudy (anonymous):

i just let jeff handle it since im a lazy retrice

OpenStudy (anonymous):

lol thanks anyways jay:)

OpenStudy (anonymous):

cramer's rule takes forever. I only use it if I ABSOLUTELY ABSOLUTELY need to. I know it has something to do with computer programming

OpenStudy (anonymous):

So y would be 1? And I don't even know what cramer's rule soo...yeah

OpenStudy (anonymous):

cramer's rule is really much faster, it can be done in a few mins when you know how to do it but since this problem was easy to cancel out the variables the normal method would of worked faster

OpenStudy (anonymous):

yes y is 1 now use y and z to solve for x

OpenStudy (anonymous):

So it would be: (2,1,-3)?

OpenStudy (anonymous):

Omg I understand what you were saying in history chat now-_- lol

OpenStudy (anonymous):

correct im probably going to sleep. Not being productive anymore

OpenStudy (anonymous):

Thank you guys!!!<3

OpenStudy (anonymous):

fml lol

OpenStudy (anonymous):

sure lol

OpenStudy (anonymous):

just want to note theres a small mistake with the answer 5x+5y=15 --> 15x + 15y = 45 3x+2y=10 --> - 15x - 10y = -50 -------------------------------- 0 +5y = -5 y = -1

OpenStudy (anonymous):

...aw:( So that messes up the whole problem

OpenStudy (anonymous):

not necessarily since y= -1, you can plug it in to 5x + 5y = 15 to get your x value and then plug it in to 3x+2y+3z=1 to get your z value

OpenStudy (anonymous):

Oh okay

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