Question

3. Given 4x – 8y = 8: a. Transform the equation into slope-intercept form. b. Find the slope and y-intercept of the line. c. Find the equation, in point-slope form, of the line that is perpendicular to this line and passes through the point (1, 2).

Answer 1

@samsterz

Answer 2

For the line with the equation below:
a.Transform the equation into slope-intercept form.
4x–8y=8
8y=4x-8
y=x/2-1
..
b.Find the slope and y-intercept of the line.
Standard form of equation of a line:y=mx+b, m=slope, b=y-intercept

For given equation:4x–8y=8
slope=1/2
y-intercept=-1
..
c.Find the equation, in point-slope form, of the line that is perpendicular to this line
and passes through the point (1, 2).
slope of perpendicular line=-2 (negative reciprocal of slope of given line)
point-slope form of equation: y1-y2=m(x1-x2)
using coordinates of given point (1,2),
Equation: y-2=-2(x-1)