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log4 (x^3/1024y^5)
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It's asking to expand this equation.
I'd start with the law\[\log_{a} (x/y)=\log_{a}x-\log_{a}y\]
http://www.chilimath.com/algebra/advanced/log/images/466x428xrules,P20of,P20exponents.gif.pagespeed.ic.1z7-Ekl5L5.png as @Xeph suggested, use the 2nd rule listed there first then you can use the 3rd one there
I got log4(x^3=3 log4 x... i don't think i did it right.
By my first suggestion, you should end up with\[\log_4(\frac{x^3}{1024y^5})=\log_4(x^3)-\log_4(1024y^5)\] From here, I would use the law\[\log_a(x^n)=n \log_a(x)\]
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