Question

Help with Calc! Problem attached!

Answer 1

what would be the derivative of \(\bf -2x^4\quad ?\)

Answer 2

-8x^3....

Answer 3

so there =)

Answer 4

anyhow.... derivative of a constant is 0, thus if you just add a -1, the derivative remains, while y(0) will yield the constant

Answer 5

ok so... i still dont get how to do the problem

Answer 6

\(\bf y=-2x^4\qquad \cfrac{dy}{dx}=-8x^3\\ \quad \\
y=-2x^4-1\qquad \cfrac{dy}{dx}=-8x^3-0\implies -8x^3\\ \quad \\
y(0)=-2(0)^4-1\implies y(0)=-1\)

Answer 7

but y=-2x^4 isnt right.. is there more to the problem?

Answer 8

tried with the -1 yet?

Answer 9

@jdoe0001 yea its not right.... my homework is online so it tells me if im wrong