can anyone help me I gotten stuck in this problem, 2x^2+x-1=0

Question

kc_kennylau · Answer

Wolfram|Alpha is the way to go.

anonymous · Answer

a website u mean?

kc_kennylau · Answer

yep that is a website for computation

kc_kennylau · Answer

anonymous · Answer

add 1 to both sides.
then subtract the x.
then sqrt it.

kc_kennylau · Answer

@AlexisEyvonne it's quadratic equation you can't do it this way :) you have to factorize it.

anonymous · Answer

what is the specific question. Are you solving for x?

kc_kennylau · Answer

yep

anonymous · Answer

like substitution in steps basically

anonymous · Answer

trying to find x then find the ys next

anonymous · Answer

solving for x you can use the quadratic equation. have you learned how to use the formula?

kc_kennylau · Answer

$2x^2+x-1=0$
$(2x-1)(x+1)=0$
$x=0.5$ or $x=-1$

anonymous · Answer

eh....sorta i know i'm suppose to factor. just was hard cause the 2x$$2x^2$$

anonymous · Answer

or you can factor it out like @kc_kennylau it's a quicker way if its possible

kc_kennylau · Answer

Did you learn cross method or completing square? :)

anonymous · Answer

yeah i realized that now x.x thank you both and yeah i learned that completing the square

kc_kennylau · Answer

|dw:1384911921982:dw|

anonymous · Answer

ohhhh see i get that way more than the completing the square

kc_kennylau · Answer

glad it helped you :D