Mathematics
8 Online
OpenStudy (anonymous):
Finf f''x when fx =cscx
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OpenStudy (kc_kennylau):
I'm trying to guide you to the answer. Sorry for not saying the answer directly.
What is csc(x)?
OpenStudy (anonymous):
It's okay I have a basic understanding cscx is -cscxcotx right?
OpenStudy (kc_kennylau):
what?
OpenStudy (kc_kennylau):
I'm asking the function itself.
OpenStudy (anonymous):
What do you mean?
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OpenStudy (kc_kennylau):
What is the definition of cosecant? :)
OpenStudy (kc_kennylau):
wait are you stuck in the first differentiation or the second differentiation
OpenStudy (anonymous):
The second
OpenStudy (kc_kennylau):
what is the value of first that you calculated? :)
OpenStudy (anonymous):
-cscxcotx
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OpenStudy (anonymous):
Then I did the product rule and got -cscxcotx (cotx)+-cscx(-csc^2x)
OpenStudy (kc_kennylau):
but mine says it's csc(x)/x...
OpenStudy (anonymous):
How ?
OpenStudy (kc_kennylau):
welcome @JAMG :D
OpenStudy (anonymous):
yep -csc x cot x :D
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OpenStudy (kc_kennylau):
wait sorry my calculator got some problem it's -cscxcotx :)
OpenStudy (anonymous):
Oh okay lol
OpenStudy (anonymous):
So how do you find the second ?
OpenStudy (kc_kennylau):
yep you used the product rule correctly :)
OpenStudy (anonymous):
put it in terms of sin and cos
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OpenStudy (kc_kennylau):
lol ok @JAMG I'll leave it to you....
OpenStudy (anonymous):
we can help together
OpenStudy (anonymous):
If I put it terms of sin and cos wouldn't that make it more complicated?
OpenStudy (kc_kennylau):
@Theanitrix that's also what i think
OpenStudy (kc_kennylau):
just expand it and you'll find the common factor :)
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OpenStudy (anonymous):
done i think what you guys get
OpenStudy (kc_kennylau):
medal'd you @JAMG :)