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Mathematics 8 Online
OpenStudy (anonymous):

Finf f''x when fx =cscx

OpenStudy (kc_kennylau):

I'm trying to guide you to the answer. Sorry for not saying the answer directly. What is csc(x)?

OpenStudy (anonymous):

It's okay I have a basic understanding cscx is -cscxcotx right?

OpenStudy (kc_kennylau):

what?

OpenStudy (kc_kennylau):

I'm asking the function itself.

OpenStudy (anonymous):

What do you mean?

OpenStudy (kc_kennylau):

What is the definition of cosecant? :)

OpenStudy (kc_kennylau):

wait are you stuck in the first differentiation or the second differentiation

OpenStudy (anonymous):

The second

OpenStudy (kc_kennylau):

what is the value of first that you calculated? :)

OpenStudy (anonymous):

-cscxcotx

OpenStudy (anonymous):

Then I did the product rule and got -cscxcotx (cotx)+-cscx(-csc^2x)

OpenStudy (kc_kennylau):

but mine says it's csc(x)/x...

OpenStudy (anonymous):

How ?

OpenStudy (kc_kennylau):

welcome @JAMG :D

OpenStudy (anonymous):

yep -csc x cot x :D

OpenStudy (kc_kennylau):

wait sorry my calculator got some problem it's -cscxcotx :)

OpenStudy (anonymous):

Oh okay lol

OpenStudy (anonymous):

So how do you find the second ?

OpenStudy (kc_kennylau):

yep you used the product rule correctly :)

OpenStudy (anonymous):

put it in terms of sin and cos

OpenStudy (kc_kennylau):

lol ok @JAMG I'll leave it to you....

OpenStudy (anonymous):

we can help together

OpenStudy (anonymous):

If I put it terms of sin and cos wouldn't that make it more complicated?

OpenStudy (kc_kennylau):

@Theanitrix that's also what i think

OpenStudy (kc_kennylau):

just expand it and you'll find the common factor :)

OpenStudy (anonymous):

done i think what you guys get

OpenStudy (kc_kennylau):

medal'd you @JAMG :)

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