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Mathematics 11 Online
OpenStudy (anonymous):

help please! The velocity as a function of time is given as v(t) = 5t−t2 in m/s and t in seconds (s). Consider the time interval from t=0 tot = 11 . Find the time before which the acceleration is positive.

OpenStudy (raffle_snaffle):

So first take the derivative of the velocity function.

OpenStudy (anonymous):

5-2t

OpenStudy (anonymous):

now what? :o

OpenStudy (nincompoop):

solve at each interval

OpenStudy (anonymous):

its positive when i plug in 2 and negative when its 3 but neither are the answer ):

OpenStudy (nincompoop):

of course

OpenStudy (anonymous):

sooooo then?

OpenStudy (nincompoop):

ask raffles

OpenStudy (raffle_snaffle):

I am thinking...

OpenStudy (nincompoop):

thinking about what?

OpenStudy (raffle_snaffle):

the question

OpenStudy (anonymous):

lol K thanks for your help nincompoop -.- get out

OpenStudy (nincompoop):

you want me to get out? because I can solve this in a snap I don't know what you're stuck on velocity is a vector, it is negative when it is going down or to the left (backwards)

OpenStudy (raffle_snaffle):

Okay help her solve it.

OpenStudy (nincompoop):

you help her :) I am interested how'd you approach her .... I mean the question

OpenStudy (raffle_snaffle):

I don't really want to help her anymore because someone "knows" how to solve the problem in a snap.

OpenStudy (raffle_snaffle):

So go!=P

OpenStudy (nincompoop):

the problem is if I solved it for her, then she wouldn't have solved it... I would have.

OpenStudy (nincompoop):

maybe I can provide a different problem of the same concept

OpenStudy (raffle_snaffle):

Walk her to the answer...

OpenStudy (nincompoop):

it is never my style to give the answer even with solutions

OpenStudy (anonymous):

ok well what did you mean by solving at each interval?

OpenStudy (nincompoop):

at a general (any) interval

OpenStudy (nincompoop):

let me ask you something, what does the t represent in the function?

OpenStudy (anonymous):

time

OpenStudy (nincompoop):

and what about the time?

OpenStudy (nincompoop):

velocity always involve what?

OpenStudy (anonymous):

position?

OpenStudy (nincompoop):

YEAH!

OpenStudy (nincompoop):

distance (position) so distance as a function of time

OpenStudy (nincompoop):

acceleration involves what?

OpenStudy (anonymous):

velocity and time

OpenStudy (nincompoop):

change in velocity to be specific

OpenStudy (nincompoop):

(velocity final - velocity initial)/delta t

OpenStudy (anonymous):

riiight

OpenStudy (nincompoop):

the vector direction of acceleration is the same as the vector direction of velocity, correct or wrong?

OpenStudy (anonymous):

correct?

OpenStudy (nincompoop):

you need to be certain

OpenStudy (nincompoop):

or I will have @hero help you he's usually good at pointing out all the proper rudiments

OpenStudy (raffle_snaffle):

a(t)-5-2t solve for t

OpenStudy (raffle_snaffle):

Set a(t)=0 and solve for t

OpenStudy (anonymous):

OMG THANK YOU RAFFLE!

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