PLEASE HELPPPPPPPPPPPPPP !!!!!!!!!!!!!! what is the solution to x=sqrt-x+6 a. 2 & -3 b. -2 & 3 c. -3 d. 2
you actually mean sqrt-x as in \(\sqrt{-x}\)?
yes
oh wait you actually mean \(\sqrt{-x+6}\) not \(\sqrt{-x}+6\)
Square both sides :)
on the question its the first one
Just square both sides first :) can we do this step by step?
To be honest I have NOOOOOOO idea what im doing ! Im failing algebra 2 EXTREMELY !!! but if you can go through it thats fine too.. ILL TRY LOL :)
Could you square both sides? :)
would the square root be -x ?
well the sqrt isn't just to -x but to (-x+6) as a whole...
So we have: \[x=\sqrt{-x+6}\] Squaring both sides and we get: \[x^2=-x+6\]
any problem till here? :)
i dont understand how you get the x ?
wait are you in a hurry
lol, well im taking care of my little baby, thats why im so slow on replying ....
i'm also helping other ppl too, so i may also be slow :)
ok, so how do i get the x ?
Do you know how to do quadratic equations? :)
I SUCK AT THOSE
http://www.youtube.com/watch?v=2ZzuZvz33X0 and http://www.youtube.com/watch?v=bNQY0z76M5A will help you :D (sorry for the length of these videos)
I'm not providing the direct answer, because the answer is useless. What you need is not the answer, it's how to do more questions of this kind.
i went through each one & cant find it
x=2, so its D
and im 100% sure
\[x=\sqrt{-x+6}\]\[x^2=-x+6\]\[x^2+x-6=0\]\[(x-2)(x+3)=0\]\(x-2=0\) or \(x+3=0\) \(x=2\) or \(x=-3\) Therefore it's A and i'm 100% sure.
Lol ! wow . 2 different answers and both of u are sure , what to do lol
I'm 200% sure so believe me LOL
nah just kidding the check is here: http://www.wolframalpha.com/input/?t=crmtb01&f=ob&i=x%3Dsqrt(-x%2B6)
LOL HE WINS sorry my maths sucks
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