What are the possible rational zeros of f(x) = 3x4 + x3 - 13x2 - 2x + 9?
Quartic equations. What. The. Hell.
I am confused on this one. According to Descartes' Rule of Signs, it has two rational zeros, correct? I got plus or minus 1 and plus or minus 3 but it says it's wrong.
you wanna try factoring it with the factor theorem?
sure?
Coz surely you can't factorize a quartic using formulas
quartic?
quartic as in linear quadratic cubic quartic quintic
okay well my lesson says to use the Rational Root Theorem
which states that p/q = possible positive rational zeros
list all number of the form \(\frac{p}{q}\) where \(p\)divides 9, i.e. \(p=1,3,9\) and \(q\) divides \(3\) so \(q=1,3\) dont forget the \(\pm\)
the list will look like \[\pm1,\pm3,\pm9,\pm\frac{1}{3},\pm\frac{1}{9}\] i think that is all of them
oh, can q also equal 1? I was under the impression that it had to equal 3.
@satellite73 do you think you can help me out with another problem real quick?
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