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Mathematics 17 Online
OpenStudy (anonymous):

Find the extreme values of f(x)=x^4 - 4x^3 -x^2 +12x -2

OpenStudy (dumbcow):

set derivative equal to 0 \[4x^{3}-12x^{2}-2x+12 = 0\]

OpenStudy (anonymous):

4x^3-12x^2-2x+12=0

OpenStudy (anonymous):

What are the extreme values though?

OpenStudy (dumbcow):

looks like all the roots are irrational so have to solve using calculator or newtons method if you know calculus http://www.wolframalpha.com/input/?i=+4x%5E3-12x%5E2-2x%2B12%3D0

OpenStudy (anonymous):

I don't know calculus... do you know the extreme values?

OpenStudy (dumbcow):

use a calculator, the link gives the approximate zeros to the derivative equation

OpenStudy (anonymous):

I dont know how to put it into a calculator though... could you?

OpenStudy (dumbcow):

haha well i meant a graphing calculator, but i already did, look at wolfram link

OpenStudy (anonymous):

Those x answers are the extremes? I thought there was supposed to be x and y values

OpenStudy (dumbcow):

wow yes the local min/max points have x,y values but to get those you have to set derivative equal to 0 then solve for "x" . That will give you the "x" coordinates where slopes are 0 thus indicating either a local min or local max (extreme values)

OpenStudy (anonymous):

Hold up haha I'm confused. Are those three x values my answers or do I need more?

OpenStudy (dumbcow):

already told you...wait what class is this? you said you dont know calculus but the 1st step to this problem was taking the derivative...lol

OpenStudy (anonymous):

Pre-calc

OpenStudy (anonymous):

So (-.94,0), (1.14,0), and (2.8,0) are my answers for extreme values?

OpenStudy (dumbcow):

hmm for your class all you are expected to do for this problem is use your graphing calculator, graph the function, then use the "calc" "max/min" graphing tool to determine those extreme values

OpenStudy (dumbcow):

"y" values are not 0 ..... the graph we did was the derivative (slope) graph so slope was 0 at those points

OpenStudy (anonymous):

so what should I write as my complete answer

OpenStudy (dumbcow):

use your graphing calculator lol dont you know how to figure out the "y" values, given the "x" values

OpenStudy (anonymous):

When I graphed it I got different values

OpenStudy (anonymous):

@dumbcow you can't help? I really need the answer to this

OpenStudy (anonymous):

Oh ok I see the max and min values! But how do I put that in (x,y) form? I see where the min and max is at what x is, but how do I formulate my answer lol

OpenStudy (dumbcow):

it gives both x and y values

OpenStudy (anonymous):

So max would be (1.14,6.14) and the mins would be (-.94, -10) and (2.8,-2.6)?

OpenStudy (dumbcow):

yeah

OpenStudy (anonymous):

So that's what I would write as my extreme values? Exactly like that?

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