What is the inverse of the relation described by y=(2x-3)^2? Please show steps! Will become a fan and give medal to best answer!!

Question

rosedewittbukater · Answer

Lets see if I remember this..

To find the inverse is to switch the x and y, then solve for y again. I'll make "V" be the square root sign.

y = (2x-3)^2
x = (2y-3)^2
2y-3 = Vx
2y = Vx + 3
y = (Vx + 3)/2

The 3 is not part of the square root.

anonymous · Answer

So only the x on the last three lines are in a square root?

rosedewittbukater · Answer

Yes

anonymous · Answer

Thank you!

rosedewittbukater · Answer

Oh I forgot one thing. Since it's a square root, the answer should be y = (+/- Vx + 3)/2

anonymous · Answer

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