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So add 7 from both sides.
here is link to lesson on completing the square http://www.purplemath.com/modules/solvquad3.htm
yes what is half of 2?
1- what is the next step?
square that number
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here is a link to a lesson with video: http://www.youtube.com/watch?v=bNQY0z76M5A
and add it to both sides \[(x+1)^2=7+1=8\]
then take the square root of both sides, don't forget the \(\pm\) that gets you to \[x+1=\pm\sqrt8\] and you are done once you subtract \(1\) from both sides
In case you're wondering how he got \((x+1)^2=8\), \(x^2+2x-7=0\) \(x^2+2x=7\) \(x^2+2x+1=7+1\) \((x+1)^2=8\)
hope we helped you :)
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