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find f'x when f(x)= 1+csc(x^2)/1-cot(x^2)
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You want the solution or just the answer
hmm answer would be just fine but if i have a question about it can i ask for your help?
here is answer http://www.wolframalpha.com/input/?i=differentiate+%281%2Bcsc%28x%5E2%29%29%2F%281-cot%28x%5E2%29%29 look down in alternate forms seems like this is just a straightforward quotient rule problem
\[\frac{d}{dx} \csc x = -\csc x \cot x\] \[\frac{d}{dx} \cot = -\csc^{2} x\]
hmm okay, so you wouldnt do a chain rule on the (X^2)?
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yes you would...i was just giving the base derivatives for your benefit
well thank you then lol but what i need help on is on what comes after finding the chain rule
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