Question

what is the axis of symmetry for f(x)=-2x^2+20x-42?

Answer 1

for a parabola

\[y = ax^2 + bx + c\]

the axis of symmetry is always

\[x = \frac{-b}{2a}\]

in our question b = 20 and a = -2... so just substitute and evaluate

Answer 2

x= -20/2(-2)

Answer 3

yep just evaluate it for the axis...

Answer 4

So x=5? Thank you

Answer 5

yes that's it.

Glad to help.

Answer 6

@campbell_st
Can you help me with this problem?
what are the coordinates of the vertex for f(x)=2x^2+4x+9?

Answer 7

dont help did black nigg

Answer 8

?..