Question

Solve the quadratic equation by completing the square. –3x^2 + 9x = 1
A. 3/2±sqrt(6)/6
B. -3±sqrt(69)/3
C. 3±sqrt(-3)/3
D. 3/2±sqrt(69)/6

Answer 1

first factor -3 from the left side

Answer 2

then u have to add the coeficient of x halved and squared to both sides of the equation

Answer 3

3x(-x + 3) = 1
I factors the -3 from the left side
I don't get what you mean by the second part though and sorry for the late reply I was eating dinner.

Answer 4

–3x^2 + 9x = 1

I like the idea about the -3, but divide by it and forget about it, rather than factor it and have it complicate your life.

x^2 - 3x = -1/3

NOW, we can worry about Completing the Square. What's next?

Answer 5

x^2 = -1/3- 3x?

Answer 6

You seem to be solving by old rules. Your instructions are to "Complete the Square"

Answer 7

x^2 = -1/3 - 1.5?

Answer 8

It says to square it

Answer 9

It says, "Completing the Square". This is a known process. Not much room for making up what it is. You must exploit this relationship: \((a+b)^{2} = a^{2} + 2ab + b^{2}\)

Answer 10

Hold on I think tk gave the basic idea to me.... i'm going to try it one sec

Answer 11

Hold