Question

so if i have points (1,4) and (-1,1) how do i get it in standard form

Answer 1

um i know how i'm just too tired to tell you i'm sorry

Answer 2

Find the slope of the straight line from the given two points:
m = (y2-y1) / (x2 - x1)

The equation of a line knowing the slope and any point is:
y - y1 = m(x - x1)

Then rearrange it to standard form to look lie: Ax + By = C

Answer 3

so how would i arrange it if i got y=4 and 3/4 x -3/4 ?

Answer 4

Slope m = (4 - 1) / (1 - (-1)) = 3/2

Equation of the line with slope 3/2 passing through (1,4) is:
y - 4 = 3/2(x - 1)
multiply both sides by 2 to get rid of the fraction
2y - 8 = 3x - 3
add -2y to both sides
-8 = 3x - 2y - 3
add 3 to both sides
-5 = 3x - 2y
or 3x - 2y = -5 is the standard form of the line.
Just to confirm put the two given points into this equation and make sure it satisfies the equation.

Answer 5

Also, when coming up with standard form Ax + By = C make sure that A > 0
If not multiply throughout by -1 to make A positive.

Answer 6

thanks