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Mathematics 21 Online
OpenStudy (christos):

Complex Numbers, Can you please tell me why this equation is legitimate ? https://www.dropbox.com/s/0w9df1skuikqvwl/Screenshot%202013-11-22%2004.37.20.jpg

OpenStudy (unklerhaukus):

\[e^{i\theta}=\cos(\theta)+i\sin(\theta)\]

OpenStudy (loser66):

if you don't understand what UnkleRhaukus said, I have a way to explain. e^2 *e^(ipi) is a positive number, and - e^2 is a negative one. How can a positive number = a negative number? except 0, but e^ something never = 0

OpenStudy (unklerhaukus):

\[e^{i\pi}=\cos(\pi)+i\sin(\pi)\\\quad=-1+i(0)=-1\]

OpenStudy (christos):

and from where is the minus?

OpenStudy (christos):

kk got iy

OpenStudy (unklerhaukus):

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