Question

solve inequality

Answer 1

im writing info

Answer 2

\[x-4=\sqrt{x+8}\]

Answer 3

x will be equal to 1

Answer 4

can u show me how plzzzzz! an dthanks

Answer 5

\[(x-4)^2 = x+8\]
\[x^2 -8x +16 = x+8\]
combine similar terms it will become
\[x^2 -9x+8 =0\]
factor
(x+9) (x-1) = 0
to check, substitute x=-9 or x=1

Answer 6

thanks:)

Answer 7

\(x-4 = \sqrt{x+8}\)

First, before ANYTHING else, think about the Domain.

\(x+8\ge 0\;or\;x \ge -8\) You tell me why?

\(x-4\ge 0\;or\;x \ge 4\) You tell me why?

After that, if we get ANY result for x that is less than 4, we will simply discard it as extraneous. It should not even be considered as a solution.

x = 1 is not correct.
x = -9 is not correct.

Answer 8

yeah thanks:)

Answer 9

Seriously. Go try them in the original equation. They fail miserably.

Answer 10

well then is the answer zero

Answer 11

No, x = 0 is also incorrect. The only suspected results are x = 1 and x = 8. (The factoring shown above was incorrect.)

x = 1 is immediately discarded as not in the Domain.
x = 8 is a solution.
x = -9 could not have been a solutions, as -9 < 1.
x = 0 could not be a solution, as 0 < 1

If you rule out ALL your suspects, there is NO solution. In this case x = 8 is the winner.

Answer 12

ohh well thats not one of my answer choices?:/

Answer 13

opps nv thanks for the help