Question

x^2-20x+96=0

Answer 1

add 4 to btoh sides and complete the square.

Answer 2

im lost?

Answer 3

Do you know how to complete the square?

Answer 4

no

Answer 5

Ok, what about factoring and quadratic formula?

Answer 6

no

Answer 7

try to factor 96 ?

Answer 8

don't know how ):

Answer 9

x^2-20x+96=0
What values added give -20?
What values multiplied together get you +96?
Hint: the values are both negative.

Answer 10

You don't know any methods for solving this?!

Answer 11

caitlynmcdaniel do you want to learn how to factor, use quadratic formula, complete the square.
All or any of these?

Answer 12

want to learn quadratic formula

Answer 13

\[x=\frac{-b±\sqrt{b^2-4ac}}{2a}\]
\[ax^2+bx+c=0\]
a- coefficient of x^2 (or of second degree)
b- coefficient of x (or of the first degree)
c- constant

The formula is only applied when the equation is set equal to ZERO.

to find a,b, and c, FOR EXAMPLE\[3x^2+6x^2+2=0\]
\[a=3,~~~~~b=6,~~~~~c=2\]

Answer 14

The way it works is that when you find the a, b, c of the equation, you plug them into the above "quadratic" formula.

tell me
a=?
b=?
c=?

Answer 15

ok so how would I apply Ax^2+bx+c to my problem then?

Answer 16

96=c A=x^2 and -20x=B

Answer 17

\[x^2-20x+96=0~~~~~~~~~~compare~~~~~this~~~~~t o~~~~~~~~~~ax^2+bx+c=0\]

Answer 18

Yes!

Answer 19

\[a=1,~~~b=-20~~~c=96\]

Answer 20

Do you see this?

Answer 21

still, try again to be accurate