x^2-20x+96=0

Question

x^2-20x+96=0

solomonzelman · Answer

add 4 to btoh sides and complete the square.

anonymous · Answer

im lost?

solomonzelman · Answer

Do you know how to complete the square?

anonymous · Answer

no

solomonzelman · Answer

Ok, what about factoring and quadratic formula?

anonymous · Answer

no

hartnn · Answer

try to factor 96 ?

anonymous · Answer

don't know how ):

shamil98 · Answer

x^2-20x+96=0
What values added give -20?
What values multiplied together get you +96?
Hint: the values are both negative.

solomonzelman · Answer

You don't know any methods for solving this?!

solomonzelman · Answer

caitlynmcdaniel do you want to learn how to factor, use quadratic formula, complete the square.
All or any of these?

anonymous · Answer

want to learn quadratic formula

solomonzelman · Answer

$$x=\frac{-b±\sqrt{b^2-4ac}}{2a}$$
$$ax^2+bx+c=0$$
a- coefficient of x^2 (or of second degree)
b- coefficient of x (or of the first degree)
c- constant

The formula is only applied when the equation is set equal to ZERO.

to find a,b, and c, FOR EXAMPLE$$3x^2+6x^2+2=0$$
$$a=3,~~~~~b=6,~~~~~c=2$$

solomonzelman · Answer

The way it works is that when you find the a, b, c of the equation, you plug them into the above "quadratic" formula.

tell me
a=?
b=?
c=?

anonymous · Answer

ok so how would I apply Ax^2+bx+c to my problem then?

anonymous · Answer

96=c   A=x^2 and -20x=B

solomonzelman · Answer

$$x^2-20x+96=0~~~~~~~~~~compare~~~~~this~~~~~t o~~~~~~~~~~ax^2+bx+c=0$$

solomonzelman · Answer

Yes!

solomonzelman · Answer

$$a=1,~~~b=-20~~~c=96$$

solomonzelman · Answer

Do you see this?

hartnn · Answer

still, try again to be accurate
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