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Mathematics 12 Online
OpenStudy (anonymous):

Cosx(cosx+1)=0

OpenStudy (anonymous):

Cos*x*cos(x+1)=0 ?

OpenStudy (anonymous):

\[\cos(x)[\cos(x)+1]=0\] solve for cos(x)=0 and cos(x)+1=0 these will give you solutions

OpenStudy (skullpatrol):

Since ab = 0 if and only if a = 0 or b = 0.

Directrix (directrix):

^^ Zero Product Property ^^ :)

OpenStudy (anonymous):

sarahusher Or not And

OpenStudy (skullpatrol):

You must solve both cos(x)=0 and cos(x)+1=0 to get all solutions.

OpenStudy (anonymous):

@AntarAzri , you have to solve both of them for a complete set of solutions. You can't just choose which one you want to solve :)

Directrix (directrix):

The Zero Product Property does state "or" although it is the inclusive "or" which in my mind is equivalent to "and" but not the "and" of the common vernacular.

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