Question

Can someone please explain how to factor this?
d^2 + 22d + 121

Answer 1

is it multiple choice

Answer 2

Yes, I have the answer, but I want to know HOW to get to the answer.

Answer 3

first combine like terms

Answer 4

23d^3? I don't know @elitlilas

Answer 5

(d+11)^2 = d^2 + 22d + 121
(d+11)(d+11) = d^2 + 22d + 121

Answer 6

remember that 11*11 =121 and 11+11=22. and you cant just add exponents like that. there are no like terms here.

Answer 7

I think people would benefit more from the process rather than the answer.

Answer 8

I know, I wasn't asking for the answer.

Answer 9

@lonnie455rich

Answer 10

if it factors, then it will present itself in the form:

(ax+b) (cx+d), expanding this out to compare parts ...

(ax+b) (cx+d) = ac x^2 + ad x + bc x + bd
= ac x^2 + (ad+bc) x + bd

comparing this to the given: d^2 + 22d + 121, assume these are xs not ds
x^2 + 22x + 121


ac x^2 = x^2 ; therefore ac=1

(ad+bc) x = 22x ; therefore ad + bc = 22

bd = 121 ... not much to therefore on that one



if we can assume that a=c=1, this can simplify to:

b+d = 22
bd = 121

if b=d=11 cant be deduced from this, then you can work it a little bit more with some substituions

Answer 11

all of this really boils down to; what 2 numbers add to get the middle term (22), and multiply together to get the last term (121)

Answer 12

THANK YOU! I wish someone would have told me that earlier! I've been trying to find a way to factor this expression for hours now. Giving you a medal. @amistre64

Answer 13

:) youre welcome, and good luck