In a circle, a 60 degree sector has area 25 pi ft^2. What is the circumference of the circle? Leave your answer in terms of pi and simplest radical form.

I don't have any idea where to start.. Help!

Question

In a circle, a 60 degree sector has area 25 pi ft^2. What is the circumference of the circle? Leave your answer in terms of pi and simplest radical form.

I don't have any idea where to start.. Help!

anonymous · Answer

area of a sector = (C/360)*r^2
where C is the angle of the sector in degrees

circumference = 2pi*r

so solve for r in the top equation, then plug in r into the second equation, ya? ^_^

anonymous · Answer

here is the first step..
25*pi = (60/360)*r^2

anonymous · Answer

So R = 2.04, right?

anonymous · Answer

Or 2.04 pi? Sorry! I'm not good with math..

anonymous · Answer

$$\frac {25*\pi}  { \frac{60}{360}} = r^2$$

\[\frac {25*\pi}  { \frac{60}{360}} = r^2\

anonymous · Answer

$$\frac {360*25*\pi} {60} = r^2$$

anonymous · Answer

can you work it out from there?