Adam has 4 dimes, 4 quarters and 4 nickels in his pocket. He pulls out 2 coins making sure to put the first one back in his pocket before picking the second. What are the odds that he pulls out 2 nickels?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (cwrw238):
don't just give the answer princess explain how you got it
OpenStudy (cwrw238):
her answer makes no sense anyway
he has a total of 12 coins in his pocket of which 4 are nickels
so what are the odds he pols out a nickel?
OpenStudy (anonymous):
You have to multiply P(getting one nickel)*P(getting one nickel) where P(getting one nickel) = (4 nickels)/(4 nickels+4 dimes +4 quarters)
OpenStudy (anonymous):
4/12 ?
OpenStudy (cwrw238):
right
so P( 1 nickel) = 4/12 = 1/3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
thank you bro
OpenStudy (cwrw238):
yw
OpenStudy (cwrw238):
though i'm female!
P(another nickel) is also 1/3
OpenStudy (anonymous):
thank you madam :p
OpenStudy (cwrw238):
the 2 picks are independent events
and are therefore multiplied together
so the final answer is 1/3 * 1/3
Still Need Help?
Join the QuestionCove community and study together with friends!