Find the x- and y-intercepts for 3x + 4y - 12 = 0.
to get x-intercept put y= 0 in 3x + 4y - 12 = 0. to get y-intercept put x= 0 in 3x + 4y - 12 = 0.
I thought it was something like that but had a total brain blank! thank you!
welcome ^_^ if you want to verify your answer, tell me what u get :)
(-4, 0) and (0, -3)
not actually 3x +0 =12 gives you x= ... ?
4............I got the +/0 backwards didn't I!
I'm sooooo dyslexic....
. (0, 3) and (4, 0) does that look better?
x is 3, y is 0 and x is 0, y is 4
yes those are correct x-intercept ----> (4,0) y-intercept ------>(0,3)
when y is 0, x is not 3 x=4 so x-int = (4,0)
I think I need to sleep.....it's 3:10 here and I worked all day.....I've got what you showed me....I'll work on it again tomorrow.....thank you for helping me!!!
sure, have a good night and sweet dreams! :) welcome ^_^
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