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Mathematics 15 Online
OpenStudy (anonymous):

how do i find sin(arccos1/4) ?

OpenStudy (turingtest):

think of the definition of cosine; what triangle does this correspond to?

OpenStudy (anonymous):

ive never solved any by drawing a triangle, do u mean use the Pythagorean thereom so I have the values of x y and r?

OpenStudy (turingtest):

exactly cosine = adjacent/hypotenuse so what does our triangle look like?

OpenStudy (anonymous):

|dw:1385237195658:dw|

OpenStudy (anonymous):

like that ??

OpenStudy (turingtest):

perfect, now what's the sine?

OpenStudy (anonymous):

well ik sine is y/r so itd be sq rt of 15 over 4

OpenStudy (turingtest):

bingo :)

OpenStudy (anonymous):

bbut how does that help me solve sin(arccos1/4) ? or is that the answer haha

OpenStudy (turingtest):

yes, that's the answer arccos(1/4) is this angle right here:|dw:1385237422860:dw|so the sine of that angle is just opposite over hypotenuse :)

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