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OpenStudy (anonymous):
OpenStudy (cwrw238):
hint the sum of 3 angles of triangle = 180degrees
so form an equation and solve for x
OpenStudy (anonymous):
\[32+2x-15+5-x=180\]
Solve for x then plug x into the equation to find the angles
what did you get?
OpenStudy (anonymous):
yea i tried and got a different answer
OpenStudy (anonymous):
What did you get?
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OpenStudy (anonymous):
wait not done ,im retrying it
OpenStudy (anonymous):
46
OpenStudy (anonymous):
\[32+2x-15+x-5=180\]
Move all the non-x values to the left side of the equal sign;
\[2x+x = 180+5+15-32\]
simplify
\[3x = 168\]
divide by 3
x = 56
To find the angles, plug 56 for the x
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
what do i do next to find the ABC
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OpenStudy (anonymous):
Since we know B = x- 5
and we know x = 56
Just plug 56 into the equation "x-5"
56-5 = 51
So B = 51 degrees
OpenStudy (anonymous):
c is 97 so what do i do next
OpenStudy (anonymous):
do i add them all together
OpenStudy (anonymous):
No - the angle measure for ABC is 51
OpenStudy (anonymous):
oh thanks nvm
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OpenStudy (anonymous):
Since all three angles of a triangle must equal 180. We can subtract the known angle measures to find angle C (ACB)
180-32-51 = 97
c = 97
OpenStudy (anonymous):
yea i didnt knoe whether to take 97 or 51 haha i was confused