help?

Question

help?

anonymous · Answer

whats your question

hero · Answer

with?

hero · Answer

@sosfrommaths, you are posting your question in @kaylaynn's question. That is considered a no-no here.

anonymous · Answer

Suppose an object moves along a horizontal path with the position function $$x(t) = 4t-t ^{2}$$ on the time interval $$0\le t \le 5$$where x is measured in meters and t is measured in seconds. find the average velocity of the object from t=0 to t=5. Make sure to state units in your answer.

anonymous · Answer

do you mean x(t)= to meters  
you would just plug t into the function for the intervals asked.

jdoe0001 · Answer

x(0)  and x(5)
how many units is their difference?

well, the average speed or velocity will be  that amount over the interval given
from 0 - 5, the interval is just 5 units, that is, 5 seconds

jdoe0001 · Answer

$\bf \cfrac{x(0)-x(5)}{[0..5]units}\implies \cfrac{x(0)-x(5)\quad meters}{5\quad seconds}$

anonymous · Answer

? its a bit messed up

anonymous · Answer

I don't think the equation editor is working right now. I couldn't get mine to work either.