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Mathematics 7 Online
OpenStudy (unklerhaukus):

7*11*13=

OpenStudy (calculusxy):

I suggest you to take the larger numbers first and then you can multiply them. (11*13) Then use that product to multiply it by 7 (x*7). That will get you your answer :)

OpenStudy (isaiah.feynman):

I can't believe you can't solve this yet you solved a logarithm problem.

OpenStudy (unklerhaukus):

11*13=10*13+13=130+13=143

OpenStudy (unklerhaukus):

7*143=7*100+7*40+7*3=700+280+21=

OpenStudy (unklerhaukus):

is this really the best method?

OpenStudy (calculusxy):

That is called the partial-products, I believe. It is kind of hard as a strategy. But I just simply Guggenheim you to multiply 11*13. Then that product (we will say x) will be multiplied by 7.

OpenStudy (calculusxy):

I don't know what "Guggenheim" means. My iPad just auto-corrected this. :(

OpenStudy (unklerhaukus):

Guggenheim = suggest?

OpenStudy (calculusxy):

Yes :)

OpenStudy (unklerhaukus):

ha ha

OpenStudy (calculusxy):

Did you arrive at your final answer?

OpenStudy (anonymous):

help!!!!!!!!!!!!

OpenStudy (unklerhaukus):

1001, its a nice result

OpenStudy (calculusxy):

@katalina13 What do you need help with?

OpenStudy (anonymous):

i have this question in the english room and nobody will help me

OpenStudy (calculusxy):

@UnkleRhaukus You are correct! And that is a "nice" result. :)

OpenStudy (kainui):

What I do is realize that 7 is really (10-3) and 13 is (10+3) which makes it easy to multiply together since that's just: (100-9). Then multiply that by 11 which is of course (10+1) and get 1000-90+100-9 and bam you can see the middle terms comes to be 10, and the last term is -9 so you really just have 1001.

OpenStudy (anonymous):

@calculusxy can you help

OpenStudy (calculusxy):

I will try to help you. Let's go and visit your post in the English section. :)

OpenStudy (unklerhaukus):

Thankyou @Kainui !, that is exactly what i was looking for

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