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center (3,2), r=5
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uh huh?
Need the equation? \[(x-3)^2+(y-2)^2=25\]
Thanks Ryan2416 . I got the same answer . Pls. can you show your working . I have (x-3^2+(y-2)^2=5^2, (x-3)+(y-2)^2
There isn't much work to show for this problem. What is needed is you must apply the formula for an equation of a circle with center (h,k) and a radius r \[ (x – h)^2 + (y – k)^2 = r^2\] you are already given h & k so all you have to do is plug it into the equation and that is how you get \[ (x – 3)^2 + (y – 2)^2 = 5^2\]
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