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OpenStudy (anonymous):
what is cos(n+1)pi
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OpenStudy (kc_kennylau):
domain of n?
OpenStudy (anonymous):
cos (npi + pi) cos is -ive in 3rd quad so -cos npi
OpenStudy (anonymous):
it can be anything.from 0 to infinity
OpenStudy (anonymous):
got ur answer @vaishnav
OpenStudy (kc_kennylau):
\[\cos[(n+1)\pi]\]\[=cos(n\pi+\pi)\]\[=\cos(n\pi)cos\pi-sin(n\pi)sin\pi\]\[=-\cos(n\pi)-0\]\[=-\cos(n\pi)\]
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OpenStudy (anonymous):
thankss@kc_kennylau and @divu.mkr
OpenStudy (kc_kennylau):
no problem :)
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