medal & fan (:
Choose the equation of the horizontal line that passes through the point (1, -5).
y = -5
x = 1
y = 1
x = -5
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OpenStudy (shamil98):
horizontally on the rectangular coordinate system is the y
so y = -5
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OpenStudy (anonymous):
thank you (: will you help me on another ?
OpenStudy (shamil98):
sure.
OpenStudy (anonymous):
Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6.
y = -6x - 15
y = -6x - 20
y = -6x + 15
y = -6x + 20
OpenStudy (shamil98):
plug in the values of x and y and m into
y = mx + b
and solve for b.
that way you find your y-intercept
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OpenStudy (anonymous):
Y=-2 -3+ -6 is that right ?
OpenStudy (shamil98):
Close.
remember
y = mx + b
(-2,-3) <-- (x,y) , m = -6
-3 = -6(-2) + b
OpenStudy (anonymous):
what is b ?
OpenStudy (shamil98):
b is your y intercept where you start graphing the line
OpenStudy (anonymous):
so, -3= -6(-2)+ b .. am i suppose to solve thatt ?
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