medal & fan (: Choose the equation of the horizontal line that passes through the point (1, -5). y = -5 x = 1 y = 1 x = -5
horizontally on the rectangular coordinate system is the y so y = -5 |dw:1385304900459:dw|
thank you (: will you help me on another ?
sure.
Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6. y = -6x - 15 y = -6x - 20 y = -6x + 15 y = -6x + 20
plug in the values of x and y and m into y = mx + b and solve for b. that way you find your y-intercept
Y=-2 -3+ -6 is that right ?
Close. remember y = mx + b (-2,-3) <-- (x,y) , m = -6 -3 = -6(-2) + b
what is b ?
b is your y intercept where you start graphing the line
so, -3= -6(-2)+ b .. am i suppose to solve thatt ?
Yeah solve for b
how? lol
-3 = -6(-2) + b -3 = 12 + b -12 -12 -15 = b
thank you.. I understand now
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