Can someone help me please?

Solve triangle ABC given that A = 56 degrees, B = 57 degrees, and b = 9.

C=64 degrees, a=10.2, c=9.8
C=67 degrees, a=10.2, c=9.88
C=67 degrees, a=8.9, c=9.88
C=66 degrees, a=8.7, c=9.88

Question

Can someone help me please?

Solve triangle ABC given that A = 56 degrees, B = 57 degrees, and b = 9. 

C=64 degrees, a=10.2, c=9.8
C=67 degrees, a=10.2, c=9.88
C=67 degrees, a=8.9, c=9.88
C=66 degrees, a=8.7, c=9.88

anonymous · Answer

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to find a and c, it's either you use the sine law or the cosine law

ranga · Answer

C = 180 - (A + B)
A = 56, B = 57.  Substitute above and solve for C
Use the sine law to find a and c.
a/sin(A) = b/sin(B) = c/sin(C)
All angles are known and b = 9.  So you can solve for a and c.