A. In guinea pigs, black fur is dominant over white fur. - A homozygous male is mated with a white female. How would I set up the parent genotypes?
For the female I say, bb For the male is it going to also be bb or BB?
BB
How do I know? Like how do you for sure know its BB
if in the question is says that he is homozygous dominant then it's BB for sure. homo = same homozygous = 2 of the same alleles
I agree with what you say, but the question does not specify
it doesn't specify if the male is black homozygous? i mean it would be a pretty boring exercise if the male was homozygous recessive you have a bb X bb cross which would give you all bb offspring
Nope it doesn't specify..
hm i would assume it's homozygous dominant simply because you'd have a bb X bb cross otherwise.
hey can u help me with my question i posted ? @aaronq
Alright, thank you both!!x
no problem, dude !
Now wait hold on.. A homozygous male is mated with a white female. Find: A. genotypes of each parent (I have set them for BB and bb) B. Genotype and Phenotype for F1 generation (I crossed the parents, got Bb for each, there fore I set up the F1 generation as Bb x Bb. Now I have ended up with 1 BB, 2 Bb, 1 bb. So genotypes/phenotypes are BB/black fur Bb/black fur bb/white fur C. genotype and phenotype for F2 generation (How do I set this one up?) @aaronq
the set that u got 1BB 2Bb 1bb is the f2 generation...u have also written the genotype...
parent-BBxbb f1-Bb f2-1BB 2Bb 1bb
Don't you have to cross it all tho?
u have already crossed 2 people of f1 generation...so the result of this cross is f2...u need not cross it again...
oh ok
and i guess if they havent specified the phenotype of male u need 2 consider both the homozygous genotypes... bbxbb and BBxbb
hm ok.
sorry i had to go but seems like you got things resolved.
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