Question

Choose the equation of the line passing through the point (1, -5) and perpendicular to y = 1 fifthx - 10.

y = 5x + 10
y = 5x
y = -5x - 10
y = -5x

Answer 1

this one?

Answer 2

y = 1 fifthx - 10
y = (1/5) x - 10

so we need to be perpendicular to this line, so the steps were to take the slope form this line, y = (1/5) x - 10, turn it into a fraction (its already a fraction so skip this step), flip the fraction upside down. and times it by -1. This will give us the slope of the perpendicular line. can you do this, we did it before on the last one?

Answer 3

I think so.

So 1 / 5 flipped is 5 /1, right? Then its opposite would be - 5 /1? But you could also just write it as -5? Right :)

@DemolisionWolf

Answer 4

excellent work, -5 is correct.
so, we now have m=-5

we create our new line equation the same way as last time, we take the standard form of
y=mx+b
plug in m,
y=-5x+b
plug in the point our new line has to pass through, (1, -5)
-5 = -5(1) + b
now solve for b..

Answer 5

0 = b?

Answer 6

So it would be y = -5x?

Answer 7

My os account is being dumb, so not to be annoying, but I'm gonna mention you just to make sure my messages go through :P @DemolisionWolf

Answer 8

y=-5x is correct ^_^

Answer 9

my account is being dumb too

Answer 10

thanks a ton!!!!

Can you see anyone's smartscores?

Answer 11

Can you make sure I did this right?

Write the equation of the line in slope-intercept form with a slope of 2 and a y-intercept of -3.

I have y = 2x + -3

Answer 12

@DemolisionWolf

Answer 13

I can't see anyon'es smart score, nor do I get my notifications

Answer 14

y = 2x + -3
correct

Answer 15

Ditto, I think theres a problem with open study for everyone.

Answer 16

Thanks! :)

Answer 17

yep ^_^