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The point P(8, 6) is on the terminal side of θ. Evaluate sin θ. someone explain it becuase i dont understand one bit
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|dw:1385495027657:dw|
hmmm I got them backwards...
|dw:1385495140629:dw|
ok
use the pythagorean theorem to find the hypotenuse, then use your soh cah toa, to get the sine function http://www.mathwarehouse.com/trigonometry/images/sohcohtoa/sohcahtoa-all.png
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i dont understand how to use the pythagorean theorem
hmm well, do you know the pythagorean theorem?
yes a little
tan 6/8 right
|dw:1385495381351:dw| \(\bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\) once you found "c" side, then use that to get the sine function \(\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies \cfrac{b}{c}\)
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