Question

pleaze

Answer 1

do you know what a "perfect square trinomial" is?

Answer 2

so... let us group the expression first \(\bf 0 = y^2 - x + 2y - 3\implies x=(y^2+2y)-3\implies x=(y^2+2y+{\bbox[2pt,white, border: 2px solid black]{\text{?}}}^2)-3\)

so what do you think is our missing value to get a "perfect square trinomial" in the parentheses?

Answer 3

\(\bf \bf 0 = y^2 - x + 2y - 3\implies x=(y^2+2y)-3\\ \quad \\\implies x=(y^2+2y+{\bbox[2pt,white, border: 2px solid black]{\text{?}}}^2)-3\) there

Answer 4

huh