Give the genotype of each of the parents in each of the following.

i. A gray, normal male mated with a gray, normal female produce 38 gray normal, 15 gray waltzers, 11 white normal and 4 white waltzers.

ii. A gray, normal male mated with a gray, normal female produce 38 gray normal, 15 gray waltzers, 11 white normal and 4 white waltzers.

iii. A gray, normal male mated with a white, waltzer female produces 8 normal, 7 gray waltzers, 9 white normal and 6 white waltzers.

I would like to check my work :)

Question

Give the genotype of each of the parents in each of the following.

i. A gray, normal male mated with a gray, normal female produce 38 gray normal, 15 gray waltzers, 11 white normal and 4 white waltzers.

ii. A gray, normal male mated with a gray, normal female produce 38 gray normal, 15 gray waltzers, 11 white normal and 4 white waltzers.

iii. A gray, normal male mated with a white, waltzer female produces 8 normal, 7 gray waltzers, 9 white normal and 6 white waltzers.

I would like to check my work :)

karatechopper · Answer

i. GGNn x ggNn
ii. GgNn x GnNn
iii. GgNn x ggnn

nincompoop · Answer

looks cool to me besides that I haven't seen any gray person out there

karatechopper · Answer

Its for mice haha

karatechopper · Answer

But is it correct? I really need to get my grade up in Bio

nincompoop · Answer

I know it is LAUGHING OUT LOUD

nincompoop · Answer

do you use punnetts? they kind of help visually, but you can also use algebra

karatechopper · Answer

how do I use algebra?

karatechopper · Answer

Yes we use punnets btw but I don't want to go through making so many squares

nincompoop · Answer

it's why I use algebra

karatechopper · Answer

So..how do u do that.

nincompoop · Answer

example:
generic problem
(A+b) (a+b) = Aa + Ab + ab + bb 

a typical color-blindedness problem where father is cy and mother Cc 
(Xc+y) (XC+Xc) = XcXC + XcXc + XCy + Xcy 
results Cc are female with normal vision
cc female colorblind 
Cy male with normal vision
cy male color blind 
ratio would be 1/2:1/2 female normal to color blind and 1/2:1/2 male normal to color blind

nincompoop · Answer

the concept applies to dihybrid-crosses as well and it gets a little complicated, and some proper statistical methods are used

karatechopper · Answer

O.o I'm not following..

nincompoop · Answer

@abb0t 
he just finished genetics and might be able to explain it to you a little clearer

karatechopper · Answer

Oh ok!

nincompoop · Answer

just as you represent letters with traits, the same goes with regular algebra problems when you assign x's and y's and z's to a particular thing

karatechopper · Answer

Ok. thanks tho nin!
But ur sure that my answers are correct?

nincompoop · Answer

i have to go to school, and if you don't get help when I come back home later tonight, I'll show you the solution

karatechopper · Answer

That works :)