What is the equation for the axis of symmetry of the quadratic
function f(x) = 2x2 + 12x - 16?

Question

What is the equation for the axis of symmetry of the quadratic
 function f(x) = 2x2 + 12x - 16?

anonymous · Answer

Will give medal please!

anonymous · Answer

first you have to find the a,b, and c. so your a is the first number of the equation , b is the second and c is the third. in this equation it is a=2 b=12 and c=-16
after that you plug your numbers into the equation: $$ \frac{ -b }{ 2(a)? }$$
so you should have $$\frac{ -12 }{ 4 }$$
divide and you get -3. 
so x=-3

anonymous · Answer

can u help me with another one please Ill medal you @nb209

anonymous · Answer

ya sure

anonymous · Answer

What is the equation for the axis of symmetry of the quadratic

anonymous · Answer

what exactly is your question?