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Mathematics 13 Online
OpenStudy (anonymous):

beginning in 2002 a sports team increased its ticket price by a constant amount each year until 2013 a ticket cost $12.50 in 2005 and $20 in 2011 how much did a ticket cost in 2002?

OpenStudy (anonymous):

Alright! Lets gets this party started. First off we are given an initial amount and an initial year and a final amount and a final year in which we could calculate the amount of increase of the price of the ticket. in 2005 the ticket cost $12.50 and then raised to $20 in 2011, SO, what we do is take the difference in price from final from initial:\[$20-$12.50 = ?\]then we take the amount of years that it took to raise to that certain amount from the initial amount:\[2011-2002 = ?\]and then we are also told that the increase of the ticket is increased by a constant amount each year, meaning the SAME amount each year, so what we do is take our answers of the difference in money and divide it by the number of years it took to find the increase of the price of the ticket for each year. \[\frac{ DifferenceInPrice }{ NumberOfYearsItTook}=PriceIncreaseOfEachYear\]since you can find the increase in price of each year, you can find the number of years it reached from the beginning (2002) to 2005 in which the price of the ticket was $12.50 and solve for the initial price of the ticket.

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